(1/9)^x=27^x-15

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Solution for (1/9)^x=27^x-15 equation: 



(1/9)^x=27^x-15

We move all terms to the left:

(1/9)^x-(27^x-15)=0



Domain of the equation: 9)^x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/9)^x-(27^x-15)=0

We get rid of parentheses

(+1/9)^x-27^x+15=0

We multiply all the terms by the denominator


(+1-27^x*9)^x+15*9)^x=0

Wy multiply elements

(+1-27^x*9)^x+135x=0

We add all the numbers together, and all the variables

135x+(+1-27^x*9)^x=0

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